Just as how you would teach multiplication to any child in the beginning. There is 1 set of 2 pencils. 1 * 2 = 2 pencils. There are 2 sets of pencils. 2 * 2 = 4 pencils. You would apply the same concept to 8/10 that any number multiplied by 1 is itself.
X-5=square root of 51
Add 5
X=5+7.14. And x= 5- 7.14
12.14. And -2.14.
D
Answer:
0.84, 84%
Step-by-step explanation:
Answer:
12 is not a solution.
Step-by-step explanation:
1. Solve for w
8w = 99
w = 99 / 8
w = 12.375
12 is not a solution.
For either square root to exist, you require that
. This is true for all
, since
is always non-negative. This means the domain of
as a function of
is all real numbers, or
or
.
Now, because
is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be
, while the maximum value of the negative root must be
. This means the range is
, or
, or
![(-\infty,-\sqrt7]\cup[\sqrt7,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-%5Csqrt7%5D%5Ccup%5B%5Csqrt7%2C%5Cinfty%29)
.
