Connect c to e and then e to a
z = -11
Steps:
8z+12 = 5z-21
Subtract 12 from both sides
8z+12-12 = 5z-21-12
Simplify
8z = 5z-33
Subtract 5z from both sides
8z-5z = 5z-33-5z
Simplify
3z = -33
Divide both sides by 3
3z/3 = -33/3
Simplify
z = -11
Hope this helps you! (:
-Hamilton1757
Answer:
The probability of 4 or fewer unsuccessful plates in one hour is 0.00752.
Step-by-step explanation:
Let <em>X</em> = number of plates that are unsuccessful.
The expected number of unsuccessful plates per hour is, <em>λ</em> = 12.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 12.
The probability function of a Poisson distribution is:
Compute the probability of 4 or fewer unsuccessful plates in one hour as follows:
P (X ≤ 4) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)
Thus, the probability of 4 or fewer unsuccessful plates in one hour is 0.00752.
The answer for your problem is 48%