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Sliva [168]
3 years ago
10

John and Jill collect 280 stamps. Out of this John collected three time as many as

Mathematics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

Jill collected 70 Stamps

John collected 210 Stamps

Step-by-step explanation:

280/4=70

Please allow me to know if my answer helped you with a thank you!

<3Miss Hawaii

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Plssssss help me ASAP!!!!!
Pani-rosa [81]

Answer:

6

Step-by-step explanation:

plug in 8 for all p so 4^2 = 16 / 8 x 3 ---> 2 x 3 = 6

6 0
3 years ago
last month Kim trained 3 times as many dogs as cats. if the total number of cats and dogs she trained last monthbis 28, how many
boyakko [2]
28 times 3 first you do 8 times 3 than 2 times 8 then add them together 
7 0
3 years ago
Find the least common denominator of the fractions 5/8, 1/18, 5/9, 9/14
OLga [1]
In order to find, Least common denominator for all of that fractions, you need to calculate the LCM of 8, 18, 9 , 14 ['cause they are denominators ]

It would be 494

So, Your Final Answer would be 494

Hope this helps!
7 0
3 years ago
Find the value <br> f(t)=2(0.4)^t<br> f(-2)=?
Nuetrik [128]

f(t) = 2(0.4)^t

F(-2) means to replace t with -2:

f(-2) = 2(0.4)^-2

f(-2) = 12.5

4 0
3 years ago
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. Find the probability
yawa3891 [41]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests which forms the Sample Space, n(S)=80

Let the Event (a friend of the bride) =A

Let the Event (a friend of the groom) =B

n(A) =59

n(B)=50

Friends of both bride and groom, n(A \cap B)=30

Therefore:

n(A \cup B)=n(A)+n(B)-n(A \cap B)\\n(A \cup B)=59+50-30\\n(A \cup B)=79

The number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(A \cup B) =\dfrac{n(A \cup B) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

4 0
3 years ago
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