We have minus signs in between b. t^2-4, c. 9x^2-100, d. 8x^2-20 and e. 4a^2-36.
But we can see..
t^2-4 has perfect square 4.
9x^2-100 has perfect squares 9 and 100.
8x^2-20 don't have perfect squares 8 and 20.
4a^2-36 has perfect squares 2 and 6.
<h3>Therefore, b. t^2-4, c. 9x^2-100 and e. 4a^2-36 expressions represent a difference in squares.</h3>
Since they are parallel, the co-efficient of x will be the same. So m=7.
Y=Mx+c. So if we substitute the values with the coordinates, we get 10= (7*4) +c . Therefore c= -18.
So the final answer is:
Y=7x - 18
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Answer:
x = 5
Step-by-step explanation:
Since both sides are given, set both sides equal to eachother.
3x + 1 = 5x - 9
Segment CM is on the left and segment MB is on the right. From now on, solve for x.
Step 1: Isolate x by itself by subtracting the lesser value
3x + 1 = 5x - 9
-3x -3x the x's on the left cross out
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1 = 2x - 9
+9 +9 having x on one side
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10 = 2x
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Step 2: Divide each side by 2 to get rid of x's coefficient
10 = 2x
/2 /2
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5 = x
Solution: x = 5
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Solving for CB: Substitute x for both sides since x = 5
3(5) + 1 = side CM
15 + 1 = side CM
16 = side CM
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Solving for CB: Solve for the other side (segment MB)
5(5) - 9 = side MB
25 - 9 = side MB
14 = side MB
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Solving for CB: Lastly, add up the sides
16 + 14 = segment CB
30 = segment CB
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Answer:
y = 300
Step-by-step explanation:
y = 250 (1+0.2)
First add the 1 and 0.2
y=250(1.2)
multiply 250 with 1.2
y = 300
:)
Answer:
x = -7/3
Step-by-step explanation: