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siniylev [52]
2 years ago
13

Find where the lines go, the answer to the riddle is seven up every morning i just need to know where the lines go!!!! will give

brainliest and i’m literally giving all my points please please help i need the answer by tomorrow!!

Mathematics
1 answer:
postnew [5]2 years ago
6 0

Answer:

Here’s what I got for this worksheet.

Step-by-step explanation:

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COSS SENSE-MAKING The sides of square ABCD are extended
dsp73

Answer: 9 in

Step-by-step explanation:

5 0
3 years ago
there are 640 students in one school. How many boys are there if it is known that 1/4 of the number of girls is equal to one six
Anna007 [38]

Answer:

960

Step-by-step explanation:

You have to figure out what 1/4th of 640 is, which is 160.

It says that number is 1/6th of boys, so you multiply by the inverse.

160x6 = 960

7 0
2 years ago
Read 2 more answers
No links
ludmilkaskok [199]

Answer:

2/5

Step-by-step explanation:

There's 5 jellybeans in the bag total and of the five, 2 of them are red, so the probability that Cynthia gives him 2 reds is 2/5.

5 0
2 years ago
Read 2 more answers
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
blondinia [14]

Answer:

Step-by-step explanation: For part 1, it makes sense that the form is y = m + c. So, it is a simply rearrangement of the equation to start with, in order to make  the subject. This is the graph in slope-intercept form. From here it is easy to see that gradient  = and the y-intercept = 490. The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0). In easy terms, the graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470. When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher, therefore we have gleaned that the new y-intercept is 531. Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:

1. Select two points on the line and write down their coordinates

2. The gradient of the line =

3. Find the change in  (Δ

4. Find the change in  (Δ

5. Divide the result of stage 3 by the result of stage 4

6. This is your gradient

7. Take one of your sets of coordinates, and arrange them in the form , where your  is the gradient you just calculated

8. There is only one variable left, which is  (the y-intercept). Simply solve for this

9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and

For example if the two points were (1, 9) and (4, 6):

Δ = 6 - 9 = -3

Δ = 4 - 1 = 3

=  = -1

I choose the point (4, 6)

6 = (-1 * 4) + c

6 = c - 4

c = 10

Therefore, generally,

Within the context of the question, I imagine the prices of the two lunch specials will be the same in the third month and hence the gradient will still be  - this means steps 1-6 can be omitted. Furthermore if the axes are clearly labelled, you may even be able to just read off the y-intercept and hence dispose with steps 1-8!

4 0
3 years ago
Ayúdenme en este ejercicio por favor
lapo4ka [179]

Para poder encontrar el número total de conjuntos de diferentes números, lo primero que debemos contar es el número de opciones para cada una de las selecciones.

A) Para el primer número tenemos 47 opciones

para el segundo número tenemos 46 opciones, pues una ya fue seleccionada.

Para el tercer número tenemos 45 opciones

Para el cuarto número tenemos 44 opciones

Para el quinto número tenemos 43 opciones

Para el sexto número, el mega número, tenemos 27 opciones.

El número total de combinaciones es igual al producto entre los numeros de opciones:

C = 47×46×45×44×43×27 = 4,969,962,360

B) Ahora sabemos que dos de los primeros 5 números tienen valores fijos A y B.

Asumamos que son el primero y segundo número.

Entonces:

El primer número es A (1 opcion)

El segundo número es B (1 opcion)

El tercer número tiene 45 opciones (por que dos ya fueron seleccionadas)

El cuarto número tiene 44 opciones

El quinto número tiene 43 opciones

El sexto número tiene 27 opciones.

Para encontrar el número total de combinaciones no solamente deberemos multiplicar los números de opciones, tambien tendremos que tener en cuenta el número de permutaciones de 2 elementos (A y B) entre los primeros 5 posibles espacios.

Para calcular esto vemos cuantas posibles opciones tiene cada uno de ellos.

El número A tiene 5 posibles posiciones (5 opciones)

El número B tiene 4 posibles posiciones (pues una esta ocupada por A)

asú, el número de permutaciones es:

P = 5*4 = 20

Asi, en este caso el número total de combinaciones es:

C = (1×1×45×44×43×27)×20 = 45,975,600

Si quieres aprender más, puedes leer:

brainly.com/question/21591279

7 0
2 years ago
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