A) 950, 900, 1000
b) 1860, 1900, 2000
c) 200, 200, 0
d) 650, 600, 1000
e) 19900, 19900, 20000
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer:
5 as 5/6 of 30= 25 and 25+5 =30
Step-by-step explanation:
Answer: SuLee jumped 2.50 more feet farther than Nate.
Step-by-step explanation: 12.75 - 10.25 = 2.50
Answer:
12.124355653
Step-by-step explanation:
don't know if you need to round but square root of 108 is 10.3923048454 and square root of 3 is 1.73205080757
