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Vanyuwa [196]
3 years ago
8

Hello please help thanks

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
It’s runoff, it would be precipitation if it was saying in a long period of time. But since it’s short, it’s runoff
Anvisha [2.4K]3 years ago
5 0

Answer:

I think Evaporation

Step-by-step explanation:

First is Evaporation then Condensation. After that it is precipitation i think i hope this helps if not please don come at me.

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5p+9c=p solve for c I am confused on how to do it
Simora [160]
Since <span><span>5p</span><span>5⁢p</span></span> does not contain the variable to solve for, move it to the right side of the equation by subtracting <span><span>5p</span><span>5⁢p</span></span> from both sides.<span><span><span>9c</span>=<span><span><span>−5</span>p</span>+p</span></span><span><span>9⁢c</span>=<span><span><span>-5</span>⁢p</span>+p</span></span></span>Add <span><span><span>−5</span>p</span><span><span>-5</span>⁢p</span></span> and <span>pp</span> to get <span><span><span>−4</span>p</span><span><span>-4</span>⁢p</span></span>.<span><span><span>9c</span>=<span><span>−4</span>p</span></span><span><span>9⁢c</span>=<span><span>-4</span>⁢p</span></span></span>Divide each term by <span>99</span> and simplify.
8 0
3 years ago
1) Determine the discriminant of the 2nd degree equation below:
Aleksandr-060686 [28]

\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

  • x is the root of the equation.
  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

❒ p(x) = x^2 + 2x + 1 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

❒ p(x) = x^2 - x - 20 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

❒ p(x) = x^2 - 3x - 4 = 0

\large{ \rm{ \longrightarrow \: x =   \dfrac{  - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3 \pm \sqrt{9  + 16} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3  \pm 5}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
Read 2 more answers
Can some one help me plz !!!!!!!!!,!<br> 25points
allsm [11]

You would multiply 6 × 5 and you would get 30.

better explanation : solution would be A = B H = 6 × 5 which would give you 30ft²

8 0
3 years ago
Consider the figure below. Which congruence transformation maps ABCD to A"B"C"D"?
Dafna1 [17]

Answer:

Should be b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone help me with prombelm number 2
VladimirAG [237]
Question 2
H(x)=x^2-5x+7

h(2)=2^2-5(2)+7
4-10+7
-6+7
1

h(-5)=-5^2-5(-5)+7
10+25+7
35+7
42

h(-8)=-8^2-5(-8)+7
16+30+7
46+7
53


a. 1
b.42
c.53
8 0
3 years ago
Read 2 more answers
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