Since <span><span>5p</span><span>5p</span></span> does not contain the variable to solve for, move it to the right side of the equation by subtracting <span><span>5p</span><span>5p</span></span> from both sides.<span><span><span>9c</span>=<span><span><span>−5</span>p</span>+p</span></span><span><span>9c</span>=<span><span><span>-5</span>p</span>+p</span></span></span>Add <span><span><span>−5</span>p</span><span><span>-5</span>p</span></span> and <span>pp</span> to get <span><span><span>−4</span>p</span><span><span>-4</span>p</span></span>.<span><span><span>9c</span>=<span><span>−4</span>p</span></span><span><span>9c</span>=<span><span>-4</span>p</span></span></span>Divide each term by <span>99</span> and simplify.

We have, Discriminant formula for finding roots:

Here,
- x is the root of the equation.
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
1) Given,
3x^2 - 2x - 1
Finding the discriminant,
➝ D = b^2 - 4ac
➝ D = (-2)^2 - 4 × 3 × (-1)
➝ D = 4 - (-12)
➝ D = 4 + 12
➝ D = 16
2) Solving by using Bhaskar formula,
❒ p(x) = x^2 + 5x + 6 = 0



So here,

❒ p(x) = x^2 + 2x + 1 = 0



So here,

❒ p(x) = x^2 - x - 20 = 0



So here,

❒ p(x) = x^2 - 3x - 4 = 0



So here,

<u>━━━━━━━━━━━━━━━━━━━━</u>
You would multiply 6 × 5 and you would get 30.
better explanation : solution would be A = B H = 6 × 5 which would give you 30ft²
Answer:
Should be b
Step-by-step explanation:
Question 2
H(x)=x^2-5x+7
h(2)=2^2-5(2)+7
4-10+7
-6+7
1
h(-5)=-5^2-5(-5)+7
10+25+7
35+7
42
h(-8)=-8^2-5(-8)+7
16+30+7
46+7
53
a. 1
b.42
c.53