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morpeh [17]
3 years ago
11

HELP ME PLEASE I NEED CORRECT ANSWER​

Mathematics
2 answers:
jeka943 years ago
6 0

Answer:

anong grade po yarn ha ha ha po

romanna [79]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

The vertex is the coordinates of the turning point of the parabola

The axis of symmetry is a vertical line passing through the vertex with equation

x = c ( where c is the x- coordinate of the vertex )

vertex = (0, 0 ) , axis of symmetry is x = 0 ( the y- axis )

(1)

vertex = (- 2, 4 ) , axis of symmetry is x = - 2

(2)

vertex = (7, 1 ) , axis of symmetry is x = 7

(4)

vertex = (- 3, - 2 ) , axis of symmetry is x = - 3

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Evaluate: g(4):g(x) = 8x2 + 9x - 7
Elden [556K]

Answer:

g(4) = 157

Step-by-step explanation:

g(x) = 8x^2 + 9x - 7

Let x  =4

g(4) = 8 * 4^2 +9*4 -7

       =8*16 +36 - 7

        =128+36-7

        =157

6 0
3 years ago
Read 2 more answers
HELPPP ASAPPP!! 50 POINTS!!!
OleMash [197]

Answer:

Part 1)

The possible multiplicities are:

x=-7 multiplicity 1

x=-3 multiplicity 3

x=2 multiplicity 1

x=5 multiplicity 2

Part 2

The factored form is

p(x)=(x+7)(x+3)^3(x-2)(x-5)^2

Step-by-step explanation:

Part 1.

The missing diagram is shown in the attachment.

The zeroes of the seventh degree polynomial are the x-intercepts of the graph.

From the graph, we have x-intercepts at:

x=-7, x=-3,   x=2, and x=5.

The multiplicities tell us how many times a root repeats.

Also, even multiplicities will not cross their x-intercept, while odd multiplicities cross their x-intercepts.

The possible multiplicities are:

x=-7 multiplicity 1

x=-3 multiplicity 3

x=2 multiplicity 1

x=5 multiplicity 2

Note that the total multiplicity must equate the degree.

Part 2)

According to the factor theorem, if x=a is a zero of p(x), then (x-a) is a factor.

Using the multiplicities , we can write the factors as:

x+7

(x+3)^3

(x-2)^1

(x-5)^2

Therefore the completely factored form of this seventh degree polynomial is p(x)=(x+7)(x+3)^3(x-2)(x-5)^2

4 0
4 years ago
Name a value for x that will complete the inequality that is shown. Then, explain why the value makes the inequality true.
Alex17521 [72]
<h3>Answer:    0.157</h3>

========================================================

Explanation:

Convert the fraction 9/50 to decimal form. You can use either long division or a calculator.

You should find that 9/50 = 0.18 which is the same as 0.180

So the original compound inequality is the same as saying 0.125 < x < 0.180

This tells us that x is between 0.125 and 0.180 where x is not equal to either endpoint. We simply need to pick anything in this interval. It can be anything you want (I recommend to use a number line to help pick a value). One such value is 0.157. There are infinitely many values you can select from.

The number 0.157 is between 0.125 and 0.180, ie  0.125 < 0.157 < 0.180

It's very similar to saying 157 is between 125 and 180, ie 125 < 157 < 180.

7 0
3 years ago
Read 2 more answers
How many subsets of {1, 2, 3, 4, 6, 8, 10, 15} are there for which the sum of the elements is 15?
stepladder [879]

Answer:

512

Step-by-step explanation:

Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7

.

For instance, if I divide the set into parts {1,2,4}

and {3,5}, the first part adds up to 7, and its complement adds up to 8

.

Once one makes that observation, the rest of the proof is straightforward. There are 25=32

different subsets of this set (including itself and the empty set). For each one, either its sum, or its complement's sum (but not both), must be ≥8. Since exactly half of the subsets have sum ≥8, the number of such subsets is 32/2, or 16.

8 0
4 years ago
Suppose a parabola has vertex (5,-3) and also passes through the point (6, 1). Write the equation of the parabola in vertex form
Alchen [17]

General form for vertex form is:

y = a(x - h)² + k

Where the vertex is the point (h, k). We know this to be (5, -3), so we can substitute the values for h and k to get:

y = a(x - 5)² - 3

We then also have another point (6, 1) that gives us an x and y. Substitute those in to leave one unknown which we can solve for:

1 = a(6 - 5)² - 3

1 = a(1)² - 3

1 = a(1) - 3

1 = a - 3

4 = a

So the equation of this parabola in vertex form is:

y = 4(x - 5)² - 3


can i have brainlist

7 0
3 years ago
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