1−w−w2=64
Step 1: Simplify both sides of the equation.
−w2−w+1=64
Step 2: Subtract 64 from both sides.
−w2−w+1−64=64−64
−w2−w−63=0
For this equation: a=-1, b=-1, c=-63
−1w2+−1w+−63=0
Step 3: Use quadratic formula with a=-1, b=-1, c=-63.
w=
−b±√b2−4ac
/2a
w=
−(−1)±√(−1)2−4(−1)(−63)
/2(−1)
w=
1±√−251/
−2
Answer:
52
Step-by-step explanation:
given that the number is a
The expression for Ten less than 5 times the value of a number is given by
5a - 10
10 times the quantity of 12 more than one-fourth of the number.
a/4 is one-fourth of number
12 more than one-fourth of the number
a/4 + 12
expression for 10 times the quantity of 12 more than one-fourth of the number. is given by
10(a/4 + 12) = 10a/4 + 12*10 = 2.5a + 120
Given that the above two expression are equal
equating them we have
5a - 10 = 2.5a + 120
adding 10 both sides
=>5a - 10+ 10 = 2.5a + 120 + 10
=> 5a = 2.5a + 130
subtracting 2.5a from both sides
=> 5a - 2.5a = 2.5a + 130 - 2.5a
=> 2.5a = 130
dividing both side by 2.5
=> a = 130/2.5 = 52
Thus, value of a is 52
Answer:
2
Step-by-step explanation:
The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2
dV/-3V^1/2 = dt

m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t
-2/3 (√V - 15) = t

That is the expression for V at time t. I hope I was able to help. Have a good day.