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muminat
3 years ago
9

How many samples of size 2 can be formed from population of size 5

Mathematics
1 answer:
klemol [59]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Is 10(x-2)=5(2x-4) infinitely many or no solution
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10x-20=10x-20, make your decision on the answer from this which they are all real numbers. Hope this will help you!
7 0
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4. Use the two patterns below. What are the first four ordered pairs formed from
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0,2,4,8

Step-by-step explanation:

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7 0
3 years ago
A spinner has 10 equally sized sections, 6 of which are gray and 4 of which are blue. The spinner
bekas [8.4K]

Answer:

6/25

Step-by-step explanation:

6/10 chance for grey.

4/10 chance for blue.

And = Multiplication

Or = Addition

6/10 times 4/10 = 24/100

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7 0
4 years ago
Hi, umm pls help<br><br> 1/6(x-5)=1/2(x+6), solve for x <br><br> And can you please explain
Mumz [18]

Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

2x-6x=36+10

 -4x=46  

-x=\frac{46}{4}=\frac{23}{2}=11 \frac{1}{2}

Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

4 0
3 years ago
) dy 2x<br> ------ = ---------------<br> dx yx2 + y
larisa86 [58]

Step-by-step explanation:

\dfrac{dy}{dx} = \dfrac{2x}{y(x^2 + 1)}

Rearranging the terms, we get

ydy = \dfrac{2xdx}{x^2 + 1}

We then integrate the expression above to get

\displaystyle \int ydy = \int \dfrac{2xdx}{x^2 + 1}

\displaystyle \frac{1}{2}y^2 = \ln |x^2 +1| + k

or

y = \sqrt{2\ln |x^2 + 1|} + k

where I is the constant of integration.

6 0
3 years ago
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