All categories

3 years ago

Please help!!

Mathematics

1 answer:

Nastasia [14]3 years ago

8 0

Answer:

Lol

Step-by-step explanation:

You might be interested in

Need help ........................

natima [27]

Answer:

m=0.833333

Step-by-step explanation:

(1/16)−3m+1=64

log((1/16)−3m+1)=log(64)

(Take log of both sides)

(−3m+1)*(log(1/16))=log(64)

−3m+1=log(64)

log(1/16)

−3m+1=−1.5

−3m+1−1=−1.5−1

(Subtract 1 from both sides)

−3m=−2.5

−3m

−3

−2.5

−3

(Divide both sides by -3)

4 0

4 years ago

Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

<u>Step-by-step explanation:</u>

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

5 0

3 years ago

2[5+2(8-6)] I need help

Sergeu [11.5K]

2[5+2(8-6)]
2[5+2(2)]
2[5+4]
2[9]
18

7 0

3 years ago

Read 2 more answers

What is the value of x in the equation below?

denis23 [38]

Answer:

Step-by-step explanation: