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7nadin3 [17]
3 years ago
5

What is an equation of the line that passes through th (3,-1) and has a slope of 2?​

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

The given point to us is (3,-1) and the slope of the line is 2 . We can use the <u>point</u><u> </u><u>slope </u>form of the line as ,

\sf\longrightarrow m ( x - x_1) = y - y_1

Substitute the values ,

\sf\longrightarrow 2( x - 3 ) = y - (-1)

Simplify LHS and RHS ,

\sf\longrightarrow 2x - 6 = y +1

Put all terms on one side ,

\sf\longrightarrow \boxed{\bf 2x - y -7=0}

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 if I make the lateral height 6, which is triple the original lateral height, the lateral surface area becomes 18.84, which is triple the original surface area

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Help please, I attached the question. Is it a!? <br> 
AVprozaik [17]

Answer:

A

Step-by-step explanation:

Recall that for a quadratic equation of the form:

0=ax^2+bx+c

The number of solutions it has can be determined using its discriminant:  

\Delta = b^2-4ac

Where:

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  • If the discriminant is negative, we have no real solutions.
  • And if the discriminant is zero, we have exactly one solution.

We have the equation:

2x^2+5x-k=0

Thus, <em>a</em> = 2, <em>b</em> = 5, and <em>c</em> = -<em>k</em>.

In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:

b^2-4ac=0

Substitute:

(5)^2-4(2)(-k)=0

Solve for <em>k</em>. Simplify:

25+8k=0

Solve:

\displaystyle k = -\frac{25}{8}

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3 years ago
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Answer:

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4 years ago
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Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

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6. The solutions to this equation are x = 2 and x = -1/3

6 0
3 years ago
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