Answer:
8.9 = z
Step-by-step explanation:
11 = 2.1 + z - subtract the 2.1 from the 11
In all cases, the events are independent. That's why we have to multiply the results.
Probability that both numbers are greater than 6 if the same number can be chosen twice.
P = 3 / 9 * 3 / 9 = 1/9 because possible outcomes are the pairs (7,8), (7,9) and (8,9).
Probability that both numbers are less than 7 if the same number can be chosen twice
P = 6 / 9 * 6 / 9 = 4/9
Probability when both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice
P = 3/9 * 2/8 = 1/12, odd numbers less than 6 are 1, 3 and 5. If the same number cannot be chosen depending on these numbers, we'll end up with 2 in possible outcome for the 2nd pair of the probability.
Probability that both numbers are even numbers if the same numbers cannot be chosen twice is
P = 4/9 * 3/9 = 4/27. The same logic is possible in this case, as well
P(x) = 1x^2 + bx + c
If -bi is a root, then +bi is the other root.
Thus, p(x) = (x+bi)(x-bi) = 1x^2 + b^2
Answer:
12/5 or 2 2/5
Step-by-step explanation:
3/5+3/5+3/5+3/5
=> (3+3+3+3) / 5
=> 12/5
=> 2 2/5
Hope it helps......
54-6= 48
5/3= 1.67
1.67*48=80.16