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tekilochka [14]
3 years ago
13

Which of the following best describes the relationship between line R and AM

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
The answer is Perpendicular is the best describes the relationship between the line r and AM.
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Answer:

934 or 935

Step-by-step explanation:

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Please answer this I REALLY REALLY REALLY NEED IT....
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The answers to this questions would be:

1. A-> (1.5, 1.5)                              5. A and B->  7 units  

2. B-> (-2, -1.5)                               6. C and D->  3 units  

3. C-> (-3.5, 2)                                7. B and D-> 1 unit

4. D-> (0.5, 0)                                 8. A and D-> 8 units

-------------------------------- WORD PROBLEMS------------------------------------------

9. 8 feet

10a. (-4, -1)                                              10b. (4, 1)


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4 years ago
Write the degree of the following polynomials.<br>a⁴+a³b²+a²b²+b⁵​
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N(n − 3) + 2(n-3)=( )(n-3)
expeople1 [14]

Answer: n = -1 n = 3

Step-by-step explanation:

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4 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
3 years ago
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