Answer:
a) 375
b) 7062.75 mm²
Step-by-step explanation:
b) We need to find the shortest possible width and length to get the smallest possible area.
To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.
The boundaries are, therefore: 19.35 - 19.45
As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.
And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.
Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:
365 * 19.35 = 7062.75 mm²
V = pi * r^2 *h
where r is the radius and h is the height of the cylinder
V = pi * 7^2 *4
V = pi* 49*4
pi is approximated by 3.14 or 22/7
V = 22/7 * 49 * 4
V = 616 units ^3
Answer:
(2, -39)
Step-by-step explanation:
f(x)=-3(x+2)^2+9
f(2)=-3(2+2)^2+9
f(2)=-3(4)^2+9
f(2)=-3(4)(4)+9
f(2)=-3(16)+9
f(2)=-48+9
f(2)=-39
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x=−2 and y=−4
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