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Serjik [45]
2 years ago
9

Which one plz answer

Mathematics
2 answers:
alexandr402 [8]2 years ago
6 0

Answer:

right isosceles

Step-by-step explanation:

pochemuha2 years ago
5 0

Answer: I believe it is right scalene

Step-by-step explanation: because it has a 90 degree angle so it is a right triangle and scalene triangles have two congruent sides but none of the sides are congruent so it is right scalene

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PLEASE HELP ASAP MARK AS BRAINLIEST
MatroZZZ [7]
Sence it is growing you are ganna want to start at 0 from where it begins as a sapling and then go right because it is adding on to how tall it is
4 0
3 years ago
What is the answer to this ?
harina [27]

Answer:

The answer is option 1.

Step-by-step explanation:

In order to solve x, you have to make x the subject, by multiplying each sides by 5, to get rid of 5 on the left side.

\frac{x}{5}  = 8

\frac{x}{5}  \times 5 = 8 \times 5

x = 40

5 0
3 years ago
A rectangular prism has a length of 114 yards, a width of 212 yards, and a height of 4 yards.
Natalija [7]

Answer:

96, 672 yards

Step-by-step explanation:

Volume = Length · width · height

Volume = 114 · 212 · 4

Volume = 96, 672 yards

6 0
2 years ago
Read 2 more answers
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
What is the answer ?
adell [148]

The most reasonable would be grams.

5 0
2 years ago
Read 2 more answers
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