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2 years ago

14x+21y+7z distribute property. Pls help. First will be awrared

Mathematics

1 answer:

laila [671]2 years ago

3 0

Answer:

7(2x+3y+z)

Step-by-step explanation:

you've got to take a 7 out of each phrase

so 14x/7= 2x

21y/7= 3y

7z/7= z

So 7(2x+3y+z)

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

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Salaries of 49 college graduates who took a statistics course in college have a mean, x overbar, of $ 65 comma 300. Assuming a

Molodets [167]

Answer: $60,540< \mu$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu$

, where $\sigma$ = Population standard deviation.

n= sample size

$\overline{x}$ = Sample mean

z* = Critical z-value .

Given : $\sigma=\$17,000$

n= 49

$\overline{x}= \$65,300$

Two-tailed critical value for 95% confidence interval = $z^*=1.960$

Then, the 95% confidence interval would be :-

$65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu$

$=65,300-(1.96)\dfrac{17000}{7}< \mu$

$=65,300-4760< \mu$

$=60,540< \mu$

Hence, the 95% confidence interval for estimating the population mean $(\mu)$ :

$60,540< \mu$

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2 years ago