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Inessa [10]
2 years ago
7

14x+21y+7z distribute property. Pls help. First will be awrared

Mathematics
1 answer:
laila [671]2 years ago
3 0

Answer:

7(2x+3y+z)

Step-by-step explanation:

you've got to take a 7 out of each phrase

so 14x/7= 2x

21y/7= 3y

7z/7= z

So 7(2x+3y+z)

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Sally works as an estimator for​ G&J Electric. She has determined that 550 feet of electrical cable will be needed to wire a
GuDViN [60]

Given :

Initial length of electric cable needed, L=550\ ft.

Later, Sally is told that the homeowner has decide to cut back from a​ three-car garage to a​ two-car garage, which will eliminate two branch​ circuits, one of 23 feet and the other of 34 feet.

To Find :

How many feet of wire will be needed​ now.

Solution :

Wire needed is given by :

Required = Total wire - ( length of 1nd branch + length of 2nd branch )

Required = 550 - ( 23 + 34 )

Required = 550 - ( 57 ) ft

Required = 443 ft

Therefore, length of wire required is 443 ft.

Hence, this is the required solution.

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3 years ago
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8 0
3 years ago
Help this has to be don today or my grade on it will be a 60
mariarad [96]

Answer:

\frac{5}{13}

Step-by-step explanation:

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2 years ago
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7 0
2 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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