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Setler [38]
4 years ago
6

Imagine that small pieces of the metals copper, magnesium and iron are placed in three test tubes labeled A, B, and C, respectiv

ely. If enough aqueous HCl is added to each tube to completely submerge the metal pieces, predict the products that will form in each test tube.
Chemistry
1 answer:
Marizza181 [45]4 years ago
8 0
A) Cu

Cu + 2HCl --> CuCl2 + H2(g)

Products predicted: Copper(II) choloride and hydrogen gas


B) Mg

Mg + 2HCl --> MgCl2 + H2

Products predicted: magnesium chloride + hygrogen gas

C) Fe

Fe +2 HCl -> FeCl2 + H2, or
2Fe +6 HCl -> 2FeCl3 + 3H2

Products predicted: Iron(II) chloride, iron (III) chloride and hydrogen gas.

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Answer:

A loud ordinary conversation following the supplied information in the question is about 4500 dB. But, in the official decibel system measure a loud conversation does not overcome 100 dB.

Explanation:

Using the supplied data of the exercise, we say that in a restaurant conversation the value is 45 dB. If we multiply this by 100 we will have a value for a laud ordinary conversation.

45×100 = 4500 dB.

but as I mentioned in the answer, in the official decibel system measure a loud conversation between 2 man reaches a maximal of 100 dB.

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A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

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If a particle had four atomic mass unit, two of which were neutrons, but had no electrons, what would the particle be?
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Answer:

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Explanation:

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Answer:

Explanation:

See attachment

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