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Setler [38]
3 years ago
6

Imagine that small pieces of the metals copper, magnesium and iron are placed in three test tubes labeled A, B, and C, respectiv

ely. If enough aqueous HCl is added to each tube to completely submerge the metal pieces, predict the products that will form in each test tube.
Chemistry
1 answer:
Marizza181 [45]3 years ago
8 0
A) Cu

Cu + 2HCl --> CuCl2 + H2(g)

Products predicted: Copper(II) choloride and hydrogen gas


B) Mg

Mg + 2HCl --> MgCl2 + H2

Products predicted: magnesium chloride + hygrogen gas

C) Fe

Fe +2 HCl -> FeCl2 + H2, or
2Fe +6 HCl -> 2FeCl3 + 3H2

Products predicted: Iron(II) chloride, iron (III) chloride and hydrogen gas.

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Licemer1 [7]
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4 years ago
In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solution of potassium dic
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Answer:

27.64 liters

Explanation:

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Mole of CH3OH = 1.9/32.04 = 0.0593 mole

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Volume of K2Cr2O7 needed = 0.0395/0.00143

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5 0
3 years ago
Solid carbon is known to react with oxygen gas to produce carbon dioxide. If a mass of 1.2g of carbon is burned in oxygen, 4.4g
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Now ,

C + O2  → CO2

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No of moles = mass of the substance/molecular mass of the substance.

In this case 1.2 g of carbon reacts with "x "g of O2 to produce 4.4 g of CO2.

No of moles of carbon in this case = 1.2÷ 12 = 0.1 moles.

No of moles of carbon dioxide formed = 4.4÷44 =0.1 moles

Thus already discussed above, 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. Hence to produce 0.1 mole of CO2 ,0.1 mole of carbon needs to react with 0.1 mole of oxygen.

Also number of moles of O2 = mass of O2÷ molar mass of O2

Substituting number of moles of O2 as 0.1 we get

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Mass of O2 (x) = 0.1 × 32= 3.2 g

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