Refer to the attachment.
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Imagine that small pieces of the metals copper, magnesium and iron are placed in three test tubes labeled A, B, and C, respectiv
1 answer:
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Answer: Reducing agent in the given reaction is .
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in is +2 and
has 0 oxidation state.
In oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is .
Answer:
114 kPa
Explanation:
Using Gay-Lussac's law you get the equation and converting celcius you get the final equation of
. After dividing 85.5 by 27+273(300) you get 0.285 and then you multiply 0.285 by 127+273 (400). You finally get 114 kPa