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Viefleur [7K]
3 years ago
6

What is a Spontaneous charge

Chemistry
1 answer:
ddd [48]3 years ago
3 0

This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.

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O3 ozone

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6. Metals like aluminum can react with _______ to form coatings that _______ corrosion. A. iron; prevent
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Answer: Option (D) is the correct answer.

Explanation:

When aluminium reacts with oxygen, it results in the formation of a layer of aluminium oxide on its surface.

This outer layer gets corroded but it forms a protective coating for the inner layers that prevents from further corrosion.

Thus, we can conclude that metals like aluminum can react with oxygen to form coatings that prevent corrosion.

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All igneous rocks have the same mineral compositions.
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Limestone is a sedimentary rock, whereas marble is metamorphic. These two rock types can be distinguished by their textures. ... 2- Gabbro and basalt are two igneous rocks having the same chemical composition, and the same minerals (plagioclase feldspar + pyroxene), but are of different origins.

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Which of the following takes place during a redox reaction? A. Electrons are gained only. B. Electrons are lost only. C. Electro
zhannawk [14.2K]
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5 0
2 years ago
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179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g
taurus [48]

Answer:

the specific heat of the unknown compound is c_u=0.412J/g \cdot C

Explanation:

Generally the change in temperature of water is evaluated as

                \Delta T = T_2 -T_1

Substituting 16.1°C for T_1 and 27.4°C for T_2

                \Delta T = 27.4 - 16.1

                       =11.3^oC

Generally the change in temperature of  unknown compound is evaluated as

                  \Delta T_u = T_3 -T_2

Substituting 27.4°C for T_2 and 94.3°C for T_3

                                    \Delta T = 94.3 - 27.4

                                           =66.9^oC

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

               H_w = mc_w \Delta T

Substituting 179.1 g  for m , 4.18 J/g.C for c_w(specific heat of water)

             H_w = 4.18 * 179.1 * 11.3

                   = 8459.6J

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

                    H_u = m_uc_u \Delta T_u

By conservation of energy law

       Heat lost  = Heat gained  

Substituting 306.9 g  for m_u , 8459.6J for H_u

           8459.6 = 306.9 * c_u * 66.9

  Therefore     c_u = \frac{8459.6}{308.9 *66.9}

                           =0.412J/g \cdot C

                   

4 0
3 years ago
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