Answer:
is formed and it has three unpaired electrons.
Explanation:
Blue 
reacts with water to produce pink colored complex.
In this complex, 
ion forms an octahedral complex with six 
ligands.
As is a weak field ligand therefore ion remains in low spin state.
Hence electronic configuration of ion in this octahedral geometry is 
with total three unpaired electrons.
Not sure what you are asking. I have two possible answers though...
It could either be more negatively charged, or valence electrons.
The more away from the nucleus a electron is, the more negatively charged it is.
The electrons on the outermost electron shell is valence electrons.
Again, I don't know what you were asking, but one of these answers may be correct.
To be able to answer this, you need to have a phase diagram of Cu-Ni alloy. Create a vertical line along 40% in the x-axis. Then, create a horizontal line along the temperature at 1,300°C. The intersection lies outside of the α-L boundary.
<em>Therefore, the system consist solely of the L-phase: 100% L.</em>
I don't know what the problem is, but here are some rues to help you out:
- All non-zero figures are significant
- When a zero falls between non-zero digits, that zero is significant.
- When a zero falls after a decimal point, that zero is significant.
- When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
- When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
