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Alex73 [517]
3 years ago
6

NEED QUICK ASSIGNMENT IS OVERDUE

Mathematics
1 answer:
mixer [17]3 years ago
6 0

I gotchu :)

1) 6r + 7 = 13 + 7r    - Subtract 6r from both sides...

   7 = 13 + r       - Subtract 13 from both sides....

<h2>  r = -6   Check answer (don't need this part)</h2>

 6(-6) + 7 = 13 + 7(-6)

  -36 + 7 = 13 -42

   -29 = -29  ( It works )

2) -14 + 6b + 7 - 2b = 1 + 5b    - Combine like terms...

   -7 + 4b = 1 + 5b        - Add 7 to both sides....

    4b = 8 + 5b       - Subtract 5b from both sides....

     -b = 8            - Divide both sides by -1

<h2>       b = -8 </h2><h2></h2>

3) 8x + 4(4x+3) = 4(6x + 4) - 4     - Distributive property

   8x + 16x + 12 = 24x + 16 - 4        Combine like terms

   24x + 12 = 24x + 12       - Both terms equal each other

    0 = 0

Since both terms equal each other, all numbres fit.

<h2>All real numbers</h2>
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Ymorist [56]
24 cubes.

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(Please consider marking this answer as Brainliest to help me advance.)
5 0
4 years ago
I don’t really understand this can someone help please?
Sidana [21]

Answer:

23 degrees

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Rewire the rational exponent as a radical
Mice21 [21]

Answer:

\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}

Step-by-step explanation:

a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}

Answer:

\large\boxed{C.\ \sqrt5}

Step-by-step explanation:

\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5

5 0
3 years ago
Write 175 as a product of its prime factors.Write your answer in index form
Brrunno [24]

Answer:

5^2 x 7

Step-by-step explanation:

5 x 5 x 7

................

6 0
3 years ago
Read 2 more answers
Some one factor 3x^2+7x-20
mylen [45]
Split it up
3x^2+12x-5x-20
group
(3x^2+12x)+(-5x-20)
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(3x)(x+4)+(-5)(x+4)
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(3x-5)(x+4)
6 0
3 years ago
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