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777dan777 [17]
2 years ago
11

i am i always lonely even i try to be happy i am lonely inside why is that so plz help me goys my heart aching my mind is not wo

rking i am just not in this world what to do guys plz help me​
Mathematics
2 answers:
Travka [436]2 years ago
6 0

Answer:

just watch bangtan bomb it will help you a lot dear.

TC.

have a great day ahead

Nesterboy [21]2 years ago
5 0

Answer:

Try to share ur feelings with ur Family and friend

And Listen BTS song !! That's it

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What is the greatest common factor for 25 and 77?
klemol [59]
The answer is 1
factors of 25 are 25, 5, 1
factors for 77 are 77, 11, 7, 1
3 0
2 years ago
Read 2 more answers
Solve 2(a + 7) = 5a - 13
timurjin [86]

Answer:

a = 9

Step-by-step explanation:

2(a + 7) = 5a - 13

We want to bring a to one side, I will choose to bring it to the right

First, expand the bracket by multiplying 2 with a + 7

2a + 14 = 5a - 13

Bring the -13 to the left by adding 13 to both sides

2a + 14 + 13 = 5a - 13 + 13

Simplify

2a + 27 = 5a

Bring the 2a to the right by subtracting 2a from both sides

2a - 2a + 27 = 5a - 2a

Simplify

27 = 5a - 2a

27 = 3a

Bring the 3 to the left by dividing both sides by 3

27÷3 = a

Simplify

a = 9

4 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
Work out the value of 3 to the power of minus 2 give your answer as a fraction
aivan3 [116]
Your answer is 3 because all you do is form it in a fraction
8 0
2 years ago
Please please help! i need to submit in 15 minutes!!!
olganol [36]

Answer:

Step-by-step explanation:

I need the question to answer please :)

4 0
1 year ago
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