This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
Do you want a whole number or a fraction?
i think its 50 im not completley for sure though
Answer:
7.716049382716049e-4 or 1,296
Step-by-step explanation:
If 6 is to the power of 8 and my mind is not mistaken. Then it's 6^8=1,679,616 and then divide that by 6 to the power of 4 is 6^4=1,296. In the end with the numbers set. 1,679,616 Divided by 1,296 or 1,296 divided by 1,679,616.
the question in English is
<span>In a triangle ABC, the measure of the BAC angle exceeds the ABC measure by 10 °, and the measure of the ACB angle, added by 30 °, is equal to twice the BAC measure. What are the measures of the angles of this triangle?
</span>
Let
A=m ∠BAC
B=m∠ABC
C=m∠ACB
we know that
A+B+C=180-----> equation 1
A=B+10-----> B=A-10------> equation 2
C+30=2A----> C=2A-30----> equation 3
substitute equation 2 and equation 3 in equation 1
A+[A-10]+2A-30]=180------> 4A=180+40-----> A=220/4-----> A=55°
B=A-10----> B=55-10-----> B=45°
C=2A-30-----> C=2*55-30----> C=80°
the answer is
m ∠BAC is 55°
m∠ABC is 45°
m∠ACB is 80°
<span>the answer in Portuguese
</span><span>Deixei
</span>A=m ∠BAC
B=m∠ABC
C=m∠ACB
<span>nós sabemos isso
</span>A+B+C=180-----> <span>equação 1
</span>A=B+10-----> B=A-10------> equação 2
C+30=2A----> C=2A-30----> equação 3
substitute equação 2 e equação 3 dentro equação 1
A+[A-10]+2A-30]=180------> 4A=180+40-----> A=220/4-----> A=55°
B=A-10----> B=55-10-----> B=45°
C=2A-30-----> C=2*55-30----> C=80°
<span>a resposta é
</span>m ∠BAC is 55°
m∠ABC is 45°
m∠ACB is 80°
