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kkurt [141]
3 years ago
15

G(x) = sqr root of x+3 What is the domain of g?

Mathematics
2 answers:
beks73 [17]3 years ago
6 0

Answer:

all \: real \: numbers \: except \:  \\ x  + 3 < 0 \\  \:  \:  \:  \: x <  - 3

maria [59]3 years ago
5 0

Answer:

X is the domain and sqr root of X+3 is the range.

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HELP DUE AT 3!!!!!!!!!!!
MrRa [10]

Answer:

3x + 12 + x = 180

4x +12 = 180

4x = 168

x = 42

(I'm guessing you're in a different timezone than I am because it's already 3:35 here)

3 0
3 years ago
What is the slope of line that passes through the points (-3,8) and (1,32)?​
larisa [96]

Answer:

6

Step-by-step explanation:

use the formula of slopes

=  \frac{y2 - y1}{x2 - x1}  \\  =  \frac{32 - 8}{1 - ( - 3)}  \\   = \frac{24}{4}  \\  = 6

8 0
3 years ago
Read 2 more answers
Solve each system using substitution or elimination. Show all required work. X^2+y^2=40 -x+y=-8
mr_godi [17]

Answer:

steps and answers in the pic..hope u can understand the calculations...

4 0
3 years ago
If you know the answer explain it plz
uranmaximum [27]

$419.88 for plan 1


$539.88 for plan 2.


She’ll save $120

6 0
3 years ago
Find two unit vectors orthogonal to a=⟨−2,−4,−2⟩a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩b=⟨−3,5,2⟩ Enter your answer so that the first non-ze
Levart [38]

Answer:

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

Step-by-step explanation:

for  a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩

a vector orthogonal to a and b can be found through the vectorial product of a and b. Thus

c= a x bc=\left[\begin{array}{ccc}i&j&k\\-2&-4&-2\\-3&5&2\end{array}\right] =  \left[\begin{array}{ccc}-4&-2\\5&2\end{array}\right]*i+\left[\begin{array}{ccc}-2&-2\\-3&2\end{array}\right]*j+\left[\begin{array}{ccc}-2&-4\\-3&5\end{array}\right]*k = 2*i  -10*j  - 22*k

then c₁=⟨2,−10,−22⟩ and c₂= - c₁= ⟨-2,10,22⟩ are orthogonal to a and b

the corresponding unit vectors are

u₁=c₁/|c₁| = ⟨2,−10,−22⟩ / √(2²+(−10)²+(−22)²) = ⟨2,−10,−22⟩/(14*√3) =  ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

then u₂= - u₁=  ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

then the unit vectors are

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

7 0
4 years ago
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