Seth has one less than twice the number of compact discs (CDs) that Jason has. Raoul has 53 more CDs than Jason. If Seth gives J
ason 25 CDs, Seth and Jason will have the same number of CDs. How many CDs did each of the three boys have to begin with?
1 answer:
S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50
2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's
R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's
S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's
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