Use Bidmas, solve all the inner brackets (), with first division, then multiplication then addition then subtraction
Answer:
b>-5
Step-by-step explanation:

Multiply by 5 to isolate b.

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.
If you put any number greater than -5, you'll output greater than - 1.
Answer:
p is approximately equal to 1.125, -1.925
Step-by-step explanation:
We can solve this first by expanding, giving us a quadratic equation in the usual ax² + bx + c format, then solving that for p:
(4p - 4)(13p + 27) = 0
52p² + 108p - 52p - 108 = 0
52p² + 52p - 108 = 0
13p² + 13p - 27 = 0
13p² + 13p = 27
p² + p = 27 / 13
p² + p + 1/4 = 27/13 + 1/4
(p + 1/2)² = 108 / 52 + 13 / 52
(p + 1/2)² = 121 / 52
p + 1/2 = ± √(121 / 52)
p = -1/2 ± 11√(1/13) / 2
At that point we can simply plug those numbers into a calculator and solve it:
p ≈ 1.125, -1.925
Easy example that shows

:
Let

.
Then

.
So

, or

, and so

.
The basic idea is to find the period of the repeating decimal, move the

digits belonging to one period over to the left of the decimal point by multiplying by

, then subtract the original repeating decimal from this new number, and finally divide by

.
A slightly more complicated example:
Let

.
Then

.
Then

, or
18×7+5 is your answer. The answer for the problem is 18×7=126.
126+5=131.