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Alika [10]
3 years ago
8

Please help !!!!!!!!!!!!!!!!

Mathematics
2 answers:
Dahasolnce [82]3 years ago
8 0

Answer:

<h2>6 in²</h2>

Step-by-step explanation:

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We have the right triangle. One leg is a base and other leg is a height.

Therefore

<em>b = 3in, h = 4in.</em>

Substitute:

A_\triangle=\dfrac{(3)(4)}{2}=\dfrac{12}{2}=6\ in^2

Eduardwww [97]3 years ago
7 0

Answer:

6 in 2.

Step-by-step explanation:

Area =  √s(s-a)(s-b)(s-c)

=  √6×(6 - 4)×(6 - 3)×(6 - 5)

=  6 inches 2.

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What is the slope of the linear function
ivann1987 [24]

Answer: 3/4 because the line runs through the points (0,-2) and (4,1).

rise/run

5 0
3 years ago
Trevon’s school is selling tickets to a fall musical. On the first day of ticket sales the school sold 13 adult tickets and 12 s
julsineya [31]

9514 1404 393

Answer:

  • adult: $7
  • student: $10

Step-by-step explanation:

Let a and s represent the prices of adult and student tickets, respectively.

  13a +12s = 211 . . . . . . ticket sales the first day

  5a +3s = 65 . . . . . . . ticket sales the second day

Subtracting the first equation from 4 times the second gives ...

  4(5a +3s) -(13a +12s) = 4(65) -(211)

  7a = 49 . . . . . . . simplify

  a = 7 . . . . . . . divide by 7

  5(7) +3s = 65 . . . . substitute into the second equation

  3s = 30 . . . . . . . subtract 35

  s = 10 . . . . . . . divide by 3

The price of one adult ticket is $7; the price of one student ticket is $10.

7 0
3 years ago
A spool contains 270 inches of wire. How many pieces of wire, each with the a length of 1 7/8 inches, can be cut from the spool?
prisoha [69]
You would be able to cut 144 pieces of wire from the spool because 270/1 7/8 (or 1.875) equals 144
6 0
3 years ago
A hose fills a hot tub at a rate of 2.48 gallons per minute. How many hours will it take to fill a 269​-gallon hot​ tub?
never [62]

Answer:

1 hour 9 minutes

Step-by-step explanation:

7 0
3 years ago
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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