Answer:
Given function:
Replace f(x) for y:
Square both sides:
This is a <u>sideways parabola</u> that opens to the <em>right</em>, with an axis of symmetry at y = 0. (Refer to attachment 1)
If we square root this again, we get:
So 
is the part of the parabola in quadrant I → (x, y)
And 
is the part of the parabola in quadrant IV → (x, -y)
(Refer to attachment 2)
Therefore, the graph of the given function is <u>attachment 3</u>.
Answer:
Common difference is 3. And the first term is 64.
Step-by-step explanation:
The differnce between 21 and 10 is 11. So there are 11 unknown numbers in between. And the difference between 37 and 4 is 33. 33/11 is equal to 3. So the pattern is minus three. the first term is 9 terms before 37. 9 times 3 is 27. 37+27 is equal to 64. so the first term is 64
\left(\mathrm{Decimal:\quad }x=-0.75\right)
hope it helps :P
Answer:
Fill in the blanks to make the following statements true. Also named the property used.
a. (-5) + (-4) = ___ + (-5),
b. 4 + __ = 4,
c. - 53 + ___ = - 53,
d. 4 + [(-5) + (7)] = [4 + (7)] + ___,
e. 25 + [(-50) + 5 ] = (25 + 5) + ___,
f. (-4) + ___ = -4,
g. 4 + (-4) = ___,
h. 5 + ___ = 0 ,
Step-by-step explanation:
Fill in the blanks to make the following statements true. Also named the property used.
a. (-5) + (-4) = ___ + (-5),
b. 4 + __ = 4,
c. - 53 + ___ = - 53,
d. 4 + [(-5) + (7)] = [4 + (7)] + ___,
e. 25 + [(-50) + 5 ] = (25 + 5) + ___,
f. (-4) + ___ = -4,
g. 4 + (-4) = ___,
h. 5 + ___ = 0 ,
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
__
2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
__
3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
__
4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
