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ivanzaharov [21]
2 years ago
11

What would you do if when you ok so he said would go?

Mathematics
1 answer:
photoshop1234 [79]2 years ago
5 0

Answer:

cheese

Step-by-step explanation:

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While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
The ratio of girls to students at a middle school is 10 to 18. If there are 270 students at the school, how many are girls?
Stells [14]
A good way of doing this problem would be to use cross multiplication of ratios
<u />\frac{10 girls}{18 students} = \frac{X girls}{270 students}

Then cross multiply

(10 girls)(270 students)=(X girls)(18 students)

2700=18x
150=x
4 0
3 years ago
Read 2 more answers
Find the sum of the numbers divisible by 7 between 30 and 500
brilliants [131]

Answer:

17822

Step-by-step explanation:

The number that are divisible by 7 between 30 and 500 are as follows :

35, 42,49,.....,497

It will form an AP with first term, a = 35 and common difference, d = 7

Let there are n terms in the AP.

nth term of an AP is given by :

a_n=a+(n-1)d

Putting all the values,

497=35+(n-1)7\\\\462=(n-1)7\\\\n-1=66\\\\n=67

Now, the sum of n terms of an AP is given by :

S_n=\dfrac{n}{2}[2a+(n-1)d]

Putting all the values,

S_n=\dfrac{67}{2}[2(35)+(67-1)7]\\\\S_n=17822

Hence, the sum of the numbers that are divisible by 7 between 30 and 500 is 17822.

6 0
3 years ago
Whatsapp is 500% in a fraction in the simplest form
PolarNik [594]
500%=0.5 which is equal to 1/2 so the answer is 1/2

8 0
3 years ago
Read 2 more answers
Pls help this assignment is missing
wel

Answer:

See below

Step-by-step explanation:

<h3>Part A</h3>

Standard form is Ax + By = C

<u>x - price of adult tickets, y - price of child tickets, the equation in the standard form is:</u>

  • 15x + 9y = 90 ⇒ 5x + 3y = 30
<h3>Part B</h3>

<u>y-intercept is obtained when x = 0</u>

  • 15*0 + 9y = 90
  • 9y = 90
  • y = 10

It represents the amount of child tickets if no adult tickets sold

<u>x-intercept is obtained when y = 0</u>

  • 15x + y*0 = 90
  • 15x = 90
  • x = 6

It represents the amount of adult tickets if no child tickets sold

<h3>Part C</h3>

<u>Converting the equation into slope-intercept form of y = mx + b</u>

  • 5x + 3y = 30
  • 3y = -5x +  30
  • y = -5/3x + 30/3
  • y = -5/3x + 10
<h3>Part D</h3>
  • The slope is -5/3. It represents the negative ratio of ticket prices

5 0
2 years ago
Read 2 more answers
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