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Galina-37 [17]
3 years ago
8

The function f is defined by f(x)=3x+k, where k is a constant. Find k, if the graph of f passes through the point (−1,8).

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

k = 11

Step-by-step explanation:

f(x)=3x+k,

We know the input is -1 so replace x with -1 and the output is 8 so replace f(x) with 9

8 = 3(-1) +k

8 = -3+k

Add 3 to each side

8+3 = -3+3+k

11= k

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<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u>

\displaystyle \large{ |a|  =  \sqrt{ {a}^{2} } }

Given a = any expressions and b = any positive numbers, zero or any expressions.

\displaystyle \large{ |a|  =  b \longrightarrow a =  \pm b}

From the Inequality, change > to equal

\displaystyle \large{ 7 + m   =   \pm12}

Subtract 7 both sides.

\displaystyle \large{  7 - 7 + m   =  \pm12 - 7} \\ \displaystyle \large{  m   =   \pm12 - 7}

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\displaystyle \large{  m   =   5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,

\displaystyle \large{  m    >  5, m < - 19}

3 0
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