Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and
.
To find:
The
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]


In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]


Using the angle sum property in triangle AOB, we get





Hence, the measure of angle AOB is 120 degrees.
Answer:
(p^2−6) (1-q(p^2-6))
Step-by-step explanation:
p^2−6−q·(p^2−6)^2
Put parentheses around the P^2-6 at the beginning of the expression
(p^2-6) -q (p^2−6)^2
Factor out (p^2−6)
(p^2−6) (1-q(p^2-6))
Answer:
Vertical stretch by a factor of 6
Step-by-step explanation:
Multiplying the function value by a constant moves its y-coordinate farther away from the x-axis by that factor. It causes a vertical stretch. Here, ...
the vertical stretch factor is 6
What is the question pls so I might be able to help