3 years ago

What percent of workers have output more than 70 units?

Mathematics

2 answers:

gayaneshka [121]3 years ago

8 0

Answer:

The Answer will be 25%.

vovangra [49]3 years ago

7 0

Answer:

30 Percent

Step-by-step explanation:

You might be interested in

Can you please help me

Levart [38]

thanks for your help I really think that it's three

5 0

3 years ago

Joe works for a shipping company. He needs to figure out how many boxes will fit in the truck. First, he figures out the size of

disa [49]

Answer:

The answer is =A2*B2*C2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Gabrielle took a Spanish test with 50 questions and answered 44 of them correctly. What percent of the questions did Gabrielle a

mrs_skeptik [129]

She answered 88% correct. 44 times 2 is 88.

7 0

3 years ago

Read 2 more answers

Lotteries are an important income source for various governments around the world. However, the availability of lotteries and ot

SashulF [63]

Answer: 0.0473

Step-by-step explanation:

Given : The proportion of gambling addicts : p=0.30

Let x be the binomial variable that represents the number of persons are gambling addicts.

with parameter p=0.30 , n= 10

Using Binomial formula ,

$P(x)=^nC_xp^x(1-p)^{n-x}$

The required probability = $P(x>5)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{10}C_6(0.3)^6(0.7)^{4}+^{10}C_7(0.3)^7(0.7)^{3}+^{10}C_8(0.3)^8(0.7)^{2}+^{10}C_9(0.3)^9(0.7)^{1}+^{10}C_{10}(0.3)^{10}(0.7)^{0}\\\\=\dfrac{10!}{4!6!}(0.3)^6(0.7)^{4}+\dfrac{10!}{3!7!}(0.3)^7(0.7)^{3}+\dfrac{10!}{2!8!}(0.3)^8(0.7)^{2}+\dfrac{10!}{9!1!}(0.3)^9(0.7)^{1}+(1)(0.3)^{10}\\\\=0.0473489874\approx0.0473$

Hence, the required probability = 0.0473

5 0

3 years ago

Alvin is 14 years older than elga's The sum of their ages is 94 what is elga'ss age

Sonja [21]

Elga’s age is 40 and Alvin’s age is 54

8 0

3 years ago

Read 2 more answers