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GaryK [48]
3 years ago
15

Um condutor acumulou 13 pontos em infração determine todas as possibilidades

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0
Oysyoydoyfoyxouxougdfyyiyydouf
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Pleaseee anybody help me with this question it’s more than one answer
Vika [28.1K]
Hey buddy
3 rd part is correct
Hope it helps :)
5 0
3 years ago
The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 15
stepladder [879]
There are 2 unknown terms in this problem 
the amount of cement the first team received is termed as 'x' hereafter 
the cement the second team received is termed as 'y'
the first team received 50 kg less, the 1st equation is as follows;

x = y - 50    after rearranging 
1) x-y = -50
for every hour 150 kg and 200 kg were used by the two teams separately 
after three hours first team used up 150*3 = 450 kg
the second team used up 200 * 3 = 600 kg
however the first team had 1.5 times as much as second team had after three hours. 
After three hours;
the amount second team had leftover was y - 600
the amount first team had leftover was x - 450
 the amount the second team had ,multiplied by 1.5 is equal to what the first team had
we can build the 2nd equation using this information

1.5 * (y-600) = x-450
1.5y - 900 = x - 450 
rearrange the equation,
 
 1.5y - x = -450 +900
2) 1.5y - x = 450 

add 1st and 2nd equations to eliminate x 
1) + 2)     (x - y = -50) + (1.5y - x = 450)
1.5y - y = 450 -50
0.5y = 400
y = 400/ 0.5
y = 800 kg
substitute y = 800 in x = y - 50
x = 800 - 50 
x = 750 kg

first team received 750 kg and second team received 800 kg


8 0
3 years ago
At a birthday party there were five more girls than boys. If the ratio of girls to boys was 4 to 3,
exis [7]

Let number if boys be x

  • No of girls=x+5

ATQ

\\ \sf\longmapsto \dfrac{x+5}{x}=\dfrac{4}{3}

\\ \sf\longmapsto 3(x+5)=4x

\\ \sf\longmapsto 3x+15=4x

\\ \sf\longmapsto 4x-3x=15

\\ \sf\longmapsto x=15

<h3>Number of girls</h3>

\\ \sf\longmapsto x+5=15+5=20

3 0
3 years ago
When two objects reach the same time-space coordinates, they generally collide with each other. How is this different from what
nikklg [1K]

Answer:

Waves superimpose upon each other when they collide, while objects do not

Step-by-step explanation:

The main difference between the collision of waves and the collision of objects is simply the superposition principle.

When waves collide, they do not do so in the same way objects do. The superposition principle explains that waves can either collide in a constructive or destructive manner.

Case A: Waves colliding in a constructive manner

When waves collide in a constructive manner, this means that they are in phase, in simpler terms, it means that they have the same shape as they move through space-time. Constructive collision leads to a formation of a bigger wave with a higher amplitude. This is how stereo speakers operate. They produce louder sounds by releasing the same audio waves, causing them to superimpose upon each other.

Case B: Waves colliding in a destructive manner:

When waves are out of phase(i.e do not have the same shape as they move through space-time) and they collide, they try to cancel each other out, leading to a new wave with a weaker amplitude. This is how noise-cancelling headphones work. They emit an equal and opposite wave sound to the noise around your ears, thus cancelling it out.

4 0
3 years ago
Select the answer from each drop down menu. In tye diagram
maria [59]

Answer:

Theres no diagram or drop down menu

lmk when you get it and i will help you

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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