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GaryK [48]
3 years ago
15

Um condutor acumulou 13 pontos em infração determine todas as possibilidades

Mathematics
1 answer:
777dan777 [17]3 years ago
3 0
Oysyoydoyfoyxouxougdfyyiyydouf
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George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends
MariettaO [177]

For the circular cover we have:

A) The area is 379.94 ft²

B) The length of the rope must be 68.2 ft

<h3>How to get the area of the cover?</h3>

Remember that the area of a circle of radius R is given by the formula:

A = pi*R^2

Where pi = 3.14

In this case, the diameter of the pool is 20ft, then the radius is:

R = 20ft/2 = 10ft

And it must extend 12 inches beyond, then the radius of the cover must be:

R = 10ft + 12in

Now, we know that 1ft = 12 in, then we can rewrite the radius as:

R = 10ft +1ft = 11ft

Then the area of the cover is:

A = 3.14*(11ft)^2 = 379.94 ft^2

B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.

Remember that the circumference of a circle of radius R is:

C = 2*pi*R

Then the length of the rope will be:

C = 2*3.14*11ft = 68.2ft

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

7 0
2 years ago
Decide whether each table could represent a proportional relationship. If the relationship could be proportional, what would be
musickatia [10]

Answer:

I'm not sure but I've attched a link that can help you calculate unit rates: https://www.calculatorsoup.com/calculators/math/unit-rate-calculator.php

Step-by-step explanation:

Hope this helps

PLEASE MARK ME BRAINLIEST!

3 0
3 years ago
I'm so confused. This question seems contradicting, and need an explanation.
Lerok [7]

Answer:

1/2 or 0.5 dollars per kg of apples

The first thing to do is to find out how much a kg of apples sells for, since the question is only asking for the selling amount of a single kg. Nothing else. Each trip gets 300 dollars and delivers fifty packs. So each Pack, or P = 300/50, or P = 6 dollars

And each pack contains 12 kg of apples, so if P = 6 dollars and P = 12 kg of apples, then 6 dollars = 12 kg of apples

then 1 kg apples = 6/12, or 1/2.

So a single Kg of apples cost 0.5 dollars

6 0
3 years ago
What is the difference between area and perimeter
alukav5142 [94]
Area is all the space that is taken up by a two dimensional object. (the inside)
Perimeter is the distance around a two dimensional object. (the outside)
7 0
3 years ago
Read 2 more answers
Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a
NARA [144]

x^3y^2+\sin(x\ln y)+e^{xy}=0

Differentiate both sides, treating y as a function of x. Let's take it one term at a time.

Power, product and chain rules:

\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}

=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}

=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}

=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)

=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)

=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}

Product and chain rules:

\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}

=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)

=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)

=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0

Isolate the derivative, and solve for it:

\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by y to get rid of that fraction in the denominator.

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}

3 0
3 years ago
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