The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay 
dollar each day</u>.
So, the total amount needed to pay for 5 days 
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....
So, the original price for one lunch special is $19.
Answer:
y=x+4
Step-by-step explanation:
from the graph
Answer:
r=0
Step-by-step explanation:
7r-5r+8=9r+8-r
This is already an equation
Combine like terms
2r+8 = 8r+8
Subtract 2r from each side
2r-2r +8 = 8r-2r +8
8 =6r+8
Subtract 8 from each side
8-8 = 6r+8-8
0 = 6r
Divide by 6
0/6 = 6r/6
0 =r
Answer:
Step-by-step explanation:
From the problem statement, we can set up the following two equations:
where 
is the number of Knicks players, and 
is the number of Nets players.
We can substitute the first equation into the second and solve for
