Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
I think there is 9.
before it was simplified it might have been 6:9
then you simplify by 2 and get 3:2.
But i might be wrong so idk
Answer:
50 feet
Step-by-step explanation:
Set up a 3-dimensional coordinate system (see the attached image).
This setup shows an axis that runs North-South (South is <u>negative</u>, North is positive), an axis that runs East-West (East is positive, West is negative), and an axis that runs Up-Down (Up is positive, Down is negative).
The two points in question are then:
First person's location (12, -20, -12), and the second person's location is (-20, 10, 12).
The distance between two points and is
Answer: m∠OPQ + (2x + 16)° = 180°
Step-by-step explanation:
Opposite angles of a cyclic quadrilateral are supplementary.
You can try then by plotting the points in.
The answer is C
Make sure by plotting in the points, lets take (-5,27)
y = 12 -3(-5)
y = 12 + 15
y = 27
27 = 27
This is correct
Lets try (-1,15)
y = 12 -3(-1)
y = 12 + 3
y = 15
15 = 15
This is correct
Lets try (8,-12)
y = 12 -3(8)
y = 12 - 24
y = -12
-12 = -12
This is correct too.
The correct ordered pairs are <span>C(-5,27),(-1,15),(8,-12)</span>