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nlexa [21]
2 years ago
12

1a. What is the product of 2x - 3 and 5x^2 - 2x + 6? Work and Answer:​

Mathematics
2 answers:
kiruha [24]2 years ago
8 0

Answer:

I dont know.. sorry.......

levacccp [35]2 years ago
8 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

  • (2x - 3) \times (5 {x}^{2}  - 2x + 6)

  • 10x {}^{ 3}  - 4 {x}^{2}  + 12x - 15 {x}^{2}  + 6x - 18

  • 10 {x}^{3}   - 19 {x}^{2}  + 18x - 18
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Find the measure of an<br> exterior angle of a regular<br> polygon with 18 sides.
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Step-by-step explanation:

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2 years ago
Use the discriminant to find the number and type of solution for x^2+6x=-9​
likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

\displaystyle \large{D =  {b}^{2}  - 4ac}

First, arrange the expression or equation in ax^2+bx+c = 0.

\displaystyle \large{ {x}^{2}  + 6x =  - 9}

Add both sides by 9.

\displaystyle \large{ {x}^{2}  + 6x + 9 =  - 9 + 9} \\  \displaystyle \large{ {x}^{2}  + 6x + 9 =  0}

Compare the coefficients so we can substitute in the formula.

\displaystyle \large{a {x}^{2}  + bx + c =  {x}^{2}  + 6x + 9 }

  • a = 1
  • b = 6
  • c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

\displaystyle \large{D =  {6}^{2}  - 4(1)(9)} \\  \displaystyle \large{D =  36 - 36} \\  \displaystyle \large{D =  0}

Since D = 0, the type of solution is one real root.

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