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Rasek [7]
3 years ago
12

Why is my internet slow even though the speed test says it is fast

Computers and Technology
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

try a new one https://www.speedtest.net/about/knowledge/faq !!

Explanation:

You might be interested in
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

6 0
3 years ago
What was the first portable computer called and who made it?
jekas [21]
It was the Osborne 1 made by Adam Osborne in 1981.
6 0
3 years ago
Whatis NOT a key factor while designing a website?
Vaselesa [24]

Answer: Complexity

Explanation: Web designing is referred as the designing of a web page for different purposes such as online business,etc. The most important factor is usability for the improvement in performance of any site and keeping it successful.

It should be user friendly so that interaction and understanding between user and web page can easy.Consistency is also a feature which ensure that web page opened in any browser should have similar quick working.

But there should be no complexity present in the web design which can cause misunderstand with the user and functioning.

7 0
3 years ago
This method is employed in order to rapidly change the locations of the website in order to ensure that no one site us used long
tester [92]

Answer:

Fast-flux

Explanation:

The techniques that is used to shift the network without shutdown of website.

4 0
4 years ago
40 POINTS I NEED THESE ANSWERS ASAP GIVE ME THE RIGHT ASNWER AND ILL PUT YOU AS THE BRAINLIEST
Law Incorporation [45]
Having a filling system and keeping a clean desk is good time management tips (True)

Your wrists should be low,relaxed and resting on the frame of the keyboard while typing (False)

A correctly formatted memo will have a complimentary closing? (False)

Which professional business memo part is keyed first?
D.) TO

to type a capital letter "T" the typist will hold the right shift key with the right little finger, and then strike "t" with the left pointer (first) finger. (True)

in a standard block style letter, key the date to print ___ from the top edge of the page
D.) Double space (DS)

A search engine can help link you to information on how to format a buisness letter. (True)
7 0
3 years ago
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