A is the correct answer to this question because AC and BC differ because the B must be changed to an A.
C. y - 3 = 2/3(x-3)
Nothing much to do here except examine each equation and plug in the numbers to see if it's true.
a. y + 3 = 3/2(x+3)
Try 3,3
3 + 3 = 3/2(3+3)
6 = 3/2(6). And no need to go further, it's obviously not equal.
b. y - 3 = 3/2(x-3)
Try 3,3
3 - 3 = 3/2(3-3)
0 = 3/2(0). OK. Let's try 6,5
5 - 3 = 3/2(6-3)
2 = 3/2(3)
2 = 9/2 And it's not true, so check the next one.
c. y - 3 = 2/3(x-3)
Try 3,3
3 - 3 = 2/3(3-3)
0 = 0. Check 6,5
5 - 3 = 2/3(6-3)
2 = 2/3(3)
2 = 2. Good. Both sample points work. This is the correct answer.
Just to be sure, let's check the next option
d. y + 3 = 2/3(x+3)
Try 3,3
3 + 3 = 2/3(3+3)
6 = 2/3(6). And doesn't match.
Answer:
No
Step-by-step explanation:
Answer:
See deduction below
Step-by-step explanation:
I will use the known inference rules (modus ponens, etc)
From d) and b),
~r
q → r
Therefore ~q (by Modus Tollens)
From a), and our previous conclusion:
p ∨ q
~q
Therefore p (by disjunctive sillogism)
Until know, we have concluded p and ~q. By e)
~q → u ∧ s
~q
Therefore u∧s. (Modus Ponens)
From p, u∧s, and c)
u∧s
s (simplification)
p (previous conclusion)
p∧s (adjuntion)
p∧s→t (Modus Ponens)
Therefore t, as we wanted to conclude.
Answer:
The image shows the graph for given function.
Step-by-step explanation:
We are given the following information in the question:
It is clear function is an exponential function and have shape similar to exponential function.
An exponential function is of the form:
,
where b is a parameter of the function and read as b raised to the power x.
The exponential function enjoys the following properties:
- If 0 < b < 1, then the graph decreases as we move from left to right.
- If b > 1, then the graph will increase as we move from left to right.
