Answer:For every right triangle, the circumcenter is always the midpoint of the hypotenuse. All four points of concurrency can themselves be concurrent! Only with an equilateral triangle will the centroid, circumcenter, incenter and orthocenter always be the same point!
Step-by-step explanation:
8:6, 16:12, 24:18 and more
Step-by-step explanation:
you just need to multiply 4x2 to get 8 and 3x2 to get 6 and then 8x2 to get 16 and 6x2 to get 12. You have to multiply the result by 2
hopes this helps :)
Step-by-step explanation:
(92-3)x2=184 is the answer
I think it’s B but I’m not for sure
Write the inequalities that are given by the :
<span>x: the number of batches of muffins
y: the number of batches of cakes
</span>Each batch of muffin requires 7 liters of milk and each batch of cakes
require 4 liters of milk.
=> liters of milk use = 7x + 4y
<span>Tania
has 56 liters of milk.=> 7x + 4y ≤ 56
Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.
The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.
The line 7x + 4y = 56 has these x and y intercepts:
y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)
x-intercept => y = 0 => 7x = 56 => x = 56/7= 8 => point (8,0)
So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.
Also, you know that x and y are restricted to be positive or zero =>
x ≥ 0
y ≥ 0.
So, the solution region is restricted to the first quadrant.
That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>
