35 if whole number
34.7 to 1 dp
34.72 to 2dp
Answers:
<h2>7. 12</h2><h2>8. -√18</h2><h2>9. √220</h2>
Step-by-step explanation:
To find out which is greater, we must eliminate the radical symbol.
#7
= 9.38083151965
9.4 < 12
#8
= -4.24264068712
-4.2 > -6
#9
= 14.8323969742
14.5 < 14.8
I'm always happy to help :)
P(allergic) = 0.15
P(both are allergic to pollen) = (0.15)² = 0.0225 (you can use the binomial probability also)
Q(NOT allergic to pollen) = 1 - 0.0225 = 0.9775
Binomial probability
Probability of NEITHER is allergic
ⁿCₓ(p)ˣ(q)ⁿ⁻ˣ
²C₀(0.15)⁰(0.9775)² = 0.9555
P(at LEAST ONE is allergic) = 1- 0.9555 = 0.0444
Answer:
All solid substances require the same temperature and heat to melt them.
Step-by-step explanation:
Depending on the substance, the required heat to melt it changes, and is not the same for every solid.
So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.
