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Ira Lisetskai [31]
3 years ago
11

Please help me!!!! Super confused

Mathematics
1 answer:
valkas [14]3 years ago
4 0
The correct answer to 38 is B
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7). John had 9 pieces of gum at the
Dmitry_Shevchenko [17]

Answer:

9-1=8

Step-by-step explanation:

he started with 9 but at the end of the day he had 8. meaning he ate 1 peice

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2 years ago
Yikes mctugg bought 1/2pound of potato salad . He ate 2/3of it for lunch .How much potato salad was left for an afternoon snack
Anna007 [38]

\frac{1}{2}  -  \frac{2}{3}( \frac{1}{2}) =  \frac{1}{2} -  \frac{2}{6} =  \frac{3}{6} -  \frac{2}{6} =  \frac{1}{6} pound
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3 years ago
What is the mean, outlier & mean without outlier for 4; 4; 5; 6; 8; 9; 27
aleksley [76]

Answer:

the mean is 9.

Step-by-step explanation:

<h2>mean=<u>4+4+5+6+8+9+27</u></h2>

7

<h2>= <u>63</u></h2><h2> 7</h2><h2> 9 is the answer.</h2>

5 0
3 years ago
The sum of angle V and angle W is 90 degrees. If cos W = 5/13, what is sin V? A. 5/13 B. 12/13 C.12/5 D. 13/5
Savatey [412]

Answer:

I think the answer to the question should be C

Step-by-step explanation:

3 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
3 years ago
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