f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
The battery would be $. 50 meaning the torch is $2.00. 2 dollars is 80% of $2.50 meaning the torch is 80% of the total price.
Well, you are subtracting g(x) from f(x) so:
√x-x-(2x^3-√x-x) which is:
√x-x-2x^3+√x+x (you have your signs wrong at the bottom of your post)
Now you would simply combine like terms (do your addition and subtraction of like terms)
-2x^3+2√x
So the answer is D.
Answer:
c represents the number of classes
6 + 5c = 6c
Can you solve for c and answer?
