The bb and j was the source of the questions
Answer:
Step-by-step explanation:
if we have 5^22 and 5^26
5^26= 5^22 x5^4
5^26 is bigger by the number 5^4
<span>What is the next step in the proof? Choose the most logical approach. Statement: ∠1≅∠8 and ∠2≅∠7 Reason: Congruent Supplements Theorem Statement: m∠3+m∠4=180° and m∠7+m∠8=180° Reason: Linear Pair Theorem Statement: m∠3+m∠5=180° and m∠4+m∠6=180° Reason: definition of supplementary angles Statement: ∠7≅∠6 and ∠8≅∠5 Reason: Vertical Angles Theorem Done </span>
Try to imagine this word problem, there is a wall and a ladder leaning against it, the space from the bottom of the ladder is labeled 6 and the length of the height the ladder reaches on the wall is 8. Imagine this as a right triangle now, where the length of the ladder is the hypotenuse and the length of the legs of the triangle is 6 and 8. Because we know this, we can use the Pythagorean theorem, a^2+b^2=c^2
We then plug in the values and you get 6^2+8^2=c^2
When you simplify, you get 36+64=c^2 which is c^2=100
When you solve for c, you get c=10 which would be the length of the ladder :)
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
