X=12
(10(12)-20) = 120-20 = 100
(6(12)+8) = 72+8=80
100+80 = 180
Answer:
Option a) 50% of output expected to be less than or equal to the mean.
Step-by-step explanation:
We are given the following in the question:
The output of a process is stable and normally distributed.
Mean = 23.5
We have to find the percentage of output expected to be less than or equal to the mean.
Mean of a normal distribution.
- The mean of normal distribution divides the data into exactly two equal parts.
- 50% of data lies to the right of the mean.
- 50% of data lies to the right of the mean
Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
Answer:
Q.5 ab=cd
Q.6 ad=bc
Q.7 ce=ae
Q.8 eb=ed
Q.9 angle D=angle B (opposite angle of parallelogram are equal)
let other angle of parallelogram be x.
angle A+angle B +angle C + angle D= 360° (sum of quadrilateral is 360°)
x+130°+x+130°=360°
2x+260°=360°
2x=360°-260°
2x=100°
x=100/2
x=50°
Q.10 similarly, angle b= angle d
let other angle be x.
x+61°+ x+61°=360°
2x+122°=360°
2x=360°+122°
2x=238°
x=238°/2
x=119°
Q.11 in quadrilateral opposite angles are equal and opposite angle of parallelogram are equal.
Q.12 in quadrilateral opposite angle are equal and opposite angle of parallelogram are equal.
Q.13 in quadrilateral opposite sides are equal and opposite sides are parellel and this property is also present in parallelogram.
q.14 in quadrilateral diagonal bisected each other and diagonal of parallelogram also bisect each other.
Total bill-$67.95
each friends owes about $16.99
