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Shkiper50 [21]
3 years ago
10

Which point below is not on the graph A.)(-13, 7) B.)(-35, 1) C.)(11, 5) D.)(27, 3)

Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

It is B

Step-by-step explanation:

Because their isnt a square root fpr 51

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The correct answer is 37.7 sorry for the late response D;
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the ordered pairs shown represent a relation: (3, 2) (5, 1) (6, 0) (7, 4) (5, 3). Which number is part of the domain relationshi
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Calculate the median for the set of numbers:<br><br> 35, 33, 15, 32, 2, 28, 42
777dan777 [17]

Answer:

32

Step-by-step explanation:

To find the median, we need to put the numbers in order from smallest to largest

35, 33, 15, 32, 2, 28, 42

2, 15, 28, 32, 33, 35, 42

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So the 4th number is the median

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7 0
4 years ago
Read 2 more answers
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

7 0
3 years ago
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