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Katena32 [7]
2 years ago
7

5x+15y=12 ordered pair are solution to the equation

Mathematics
1 answer:
gayaneshka [121]2 years ago
5 0

Let's solve for x.

5x+15y=12

Step 1: Add -15y to both sides.

5x+15y+−15y=12+−15y

5x=−15y+12

Step 2: Divide both sides by 5.

5x

5

=

−15y+12

5

x=−3y+

12

5

Answer:

x=−3y+12/5

Let's solve for y.

5x+15y=12

Step 1: Add -5x to both sides.

5x+15y+−5x=12+−5x

15y=−5x+12

Step 2: Divide both sides by 15.

15y

15

=

−5x+12

15

y=

−1

3

x+

4

5

Answer:

y=-1/3x+4/5

Hope this helps!

-Josh

brainliest?

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3 years ago
If an event has a 55% chance of happening in one trial, how do I determine the chances of it happening more than once in 4 trial
aev [14]

The chances of it happening more than once in 4 trials is 13%

<h3>How to determine the number</h3>

From the information given, we have can deduce that;

Probability of 1 trial = 55%

= 55/ 100

Find the ratio

= 0. 55

We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

Then the probability of it happening in 1 in 4 trials is given as;

P(1/4 trials) = 1/ 4 × 55%

P(1/4 trials) = 1/ 4 × 0. 55

Put in decimal form

P(1/4 trials) = 0. 25 × 0. 55

P(1/4 trials) = 0. 138

But we have to know the percentage

= 0. 138 × 100

Multiply the values, we have

= 13. 8 %

Thus, the chances of it happening more than once in 4 trials is 13%

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6 0
2 years ago
Which expression is equivalent to 5 (2 + 7)?
SOVA2 [1]
The answer wold be 5(2)+5(7)
6 0
3 years ago
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Given the linear equation y = 10x - 11.
grigory [225]
Y 10x - 13 should be right
4 0
3 years ago
Select the ordered pairs that satisfy the equation y=1/5x.Check all that apply.
vovikov84 [41]

Answer: C, E, F

Step-by-step explanation:

  1. Plug in the "x" and "y" values from the ordered pairs into the equation.
  2. For A: 3 = \frac{1(5)}{5} → 3 ≠ 1 → A is eliminated.
  3. For B: 5 = \frac{1(1)}{5} → 5 ≠ \frac{1}{5} → B is eliminated.
  4. For C: 2 = \frac{1(10)}{5} → 2 = 2 → C satisfies the equation.
  5. For D: 10 = \frac{1(4)}{5}→ 10 ≠ \frac{4}{5} → D is eliminated.
  6. For E: -1 = \frac{1(-5)}{5}→ -1 = -1 → E satisfies the equation.
  7. For F: 3 = \frac{1(15)}{5}→ 3 = 3 → F satisfies the equation.
  8. Therefore, C, E, and F are the answers.

4 0
3 years ago
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