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Vsevolod [243]
3 years ago
12

Pls answer this question cuz i don't know what is the answer on this one

Mathematics
2 answers:
Paha777 [63]3 years ago
4 0

Answer:

1/7 because you do the inverse.

natita [175]3 years ago
3 0

Answer:

7 is b

Step-by-step explanation:

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What is 200%of 4420​
Naddik [55]

Answer:

8,840

Step-by-step explanation:

Multiply 4420 by 200% to get the answer 8840. You can also multiply 4420 by 2 to get the same answer as you would multiplying by 200%.

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Which types of reasons are not valid in a mathematical proof?
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It's definitely A, gotta be.
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The product of two numbers is 75
Lelechka [254]

Answer: 8

Step-by-step explanation: numbers are 5 and 3.

5²·3 =75

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Please help, I have so much work to do, and I have to fit in time to study for a huge test they will determine my future
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11

13

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23

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3 years ago
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An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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