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crimeas [40]
3 years ago
9

Which set of ordered pairs does not represent a function?

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0

Step-by-step explanation:

{(2, -9), (-5, -1), (-6, -3), (-5,7)}

-5 appears twice ( this is not allowed for the function)

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Estimate the answer by rounding each fraction to the nearest whole number and then adding. 13 7/10 + 10 1/8
ExtremeBDS [4]

9514 1404 393

Answer:

  24

Step-by-step explanation:

The rounded numbers are ...

  13 7/10 = 13.7 ⇒ 14

  10 1/8 = 10.125 ⇒ 10

The sum of the rounded numbers is 14 +10 = 24.

The estimate of the sum is 24.

7 0
3 years ago
Rewrite the equation without absolute value, thanks!
34kurt

Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)

Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2

Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).

So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.

y = x, if -2 < x < 3.

4 0
3 years ago
Which set of integers is not a Pythagorean triple?
Leto [7]

Answer:

10,24,25

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A sequence is defined recursively by
Andrei [34K]

9514 1404 393

Answer:

  an = 4×34^(n-1)

Step-by-step explanation:

If your recursive definition is ...

  \begin{cases}a_1=4\\a_{n}=34a_{n-1}\end{cases}

this defines a geometric sequence with a first term a1 = 4 and a common ratio of r = 34. The general form of the explicit function is ...

  a_n=a_1\times r^{n-1}

For the values shown here, the explicit definition of the sequence is ...

  \boxed{a_n=4\times 34^{n-1}}

8 0
2 years ago
A community theater uses the function p(d)=−4d2+200d−100 to model the profit (in dollars) expected in a weekend when the tickets
bixtya [17]

Answer:

price = $25

maximum profit is $2400

Step-by-step explanation:

Given the function modeled by the community theatre as

p(d)=−4d^2+200d−100

The maximum profit will be ,ade at dP/dd = 0

dP/dd = -8d + 200

0 = -8d + 200

8d = 200

d = 200/8

d = 25

hence he theatre will make maximum profit at a price of $25

Substitute d = 25 to get the maximum profit

p(25)=−4(25)^2+200(25)−100

p(25) = -2500+5000-100

p(25) = 2400

Hence the maximum profit is $2400

8 0
3 years ago
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