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BigorU [14]
3 years ago
8

Rewrite the equation without absolute value, thanks!

Mathematics
1 answer:
34kurt3 years ago
4 0

Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)

Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2

Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).

So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.

y = x, if -2 < x < 3.

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Step-by-step explanation:

we have

<em>The equation of the first line</em>

y=\frac{1}{3}x+2 ------> equation A

<em>The equation of the second line</em>

y=\frac{4}{3}x-5 ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

(-4)y=(-4)(\frac{1}{3}x+2)

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Adds equation B and equation C

y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}

<em>Find the value of x</em>

substitute the value of y

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x=13-6

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therefore

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3 years ago
Read 2 more answers
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