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tigry1 [53]
3 years ago
10

You decide to develop a new operating system to be used on mobile phones. What characteristics does it need to have?

Computers and Technology
1 answer:
guajiro [1.7K]3 years ago
6 0

The characteristics that the new operating system to be used on mobile phones should have include the following:

  • Compatibility with different hardware
  • Absence of bugs

  • Compatibility simply means how two things work together. In this case, the new operating system to be used on the mobile phones should be compatible with other phones or computer systems. It should be connected easily.

  • Also, there should be an absence of bugs. Bugs simply mean the error or the fault that can be found in a computer system. When there is a bug, it brings about unexpected results or incorrect resources.

In conclusion, the operating system should be compatible with other hardware and there should be an absence of bugs.

Read related link on:

brainly.com/question/18899940

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5 0
4 years ago
Array Challenge Have the function ArrayChallenge (arr) take the array of numbers stored in arr and return the string true if any
vampirchik [111]

Answer:

The code is given as follows,

Explanation:

Code:

#include <stdio.h>

#include <string.h>  

int n; //to store size of array  

char* ArrayChallenge(int arr[]) //function returns string true or false

{

  int i, j;

  int sum = 0;

  for(i = 0; i < n; i++)

  {

      sum = sum + arr[i]; //count sum

  }  

  for(i = 0; i < n; i++)

  {

      for(j = i+1; j < n; j++) //loop for every two elements in array

      {

          if(arr[i]*arr[j] > 2*sum) //check if proudct of two elements > 2 times sum

          {

              printf("\n%d x %d = %d, 2xSum = %d\n", arr[i], arr[j], arr[i]*arr[j], 2*sum);

              return "true"; //If proudct of two elements > 2 times sum. return true

          }

      }

  }

  return "false"; // If proudct of two elements < 2 times sum. return false

}  

int main()

{  

  printf("\nEnter size of array: ");

  scanf("%d", &n); //read size of array

  int A[n]; //array of size n

  printf("\nEnter array elements: ");

  int i;

  for(i = 0; i < n; i++)

  {

      scanf("%d", &A[i]); //read array from stdin

  }

  printf("%s\n",ArrayChallenge(A)); //ccall function and print answer

 

  return 0;

}

6 0
3 years ago
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