Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
, 
,
, 
,
, 
,
, 
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
Answer:
6c + 36 = 6(c+6)
(6*c) + (6*6) = 6(c+6)
2(3c+3) = 6c+6
(6+c)+(6+6) = neither
3c+6+3c = 6c+6
6c+12 = neither
correct me if I am wrong cuz i haven't done this in 2 years
Step-by-step explanation:
going across the top row then the bottom
Answer:
2 Paul's Survey sample only included tenth graders
Step-by-step explanation:
The reson why this is your answer is simple
Because this is true, he ONLY surveyed tenth-graders. He should have found for all of the students, including the other 1,100 students that didn't get surveyed.
Thanks!
Answer:
the nominator could be any number here
