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Alekssandra [29.7K]
3 years ago
8

Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4

Mathematics
2 answers:
sleet_krkn [62]3 years ago
5 0

Answer:

x=2 is the vertical asymptote.

horizontal asymptote is y=0

Step-by-step explanation:

Find the vertical and horizontal asymptotes

y=\frac{x^3}{(x-2)^4}

To find out the vertical asymptote, we set the denominator =0 and solve for x

(x-2)^4=0

Take fourth root on both sides

x-2=0

Add 2 on both sides , so x=2 is the vertical asymptote.

To find horizontal asymptote , we look at the degree of both numerator and denominator

Degree of numerator is 3 and the degree of denominator is 4

When the degree of numerator is less than the degree of numerator then horizontal asymptote is y=0

Here, 3 so the horizontal asymptote is y=0

alexira [117]3 years ago
4 0
The answer is A. Just took the test and got it right. 
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Find the equation of a line containing the given point and slope (10,5); m=9/20
ohaa [14]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 10}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{9}{20}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-5=\cfrac{9}{20}(x-10)\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-5=\cfrac{9}{20}x-\cfrac{9}{2}\implies y=\cfrac{9}{20}x-\cfrac{9}{2}+5\implies y=\cfrac{9}{2}x+\cfrac{1}{2}
6 0
3 years ago
Acellus
Step2247 [10]

Answer:

57 cm²

Step-by-step explanation:

Surface area of the yellow prism = front + back + right + left + top

✔️Area of the front = L * W

L = 4 cm

W = 3 cm

Area of the front = 4*3 = 12 cm²

✔️Area of the back = L * W

L = 4 cm

W = 3 cm

Area of the back = 4*3 = 12 cm²

✔️Area of the right face = L * W

L = 4 cm

W = 3 cm

Area of the right face = 4*3 = 12 cm²

✔️Area of the left face = L * W

L = 4 cm

W = 3 cm

Area of the left face = 4*3 = 12 cm²

✔️Area of the top = L * W

L = 3 cm

W = 3 cm

Area of the top = 3*3 = 9 cm²

✅Total = 12 + 12 + 12 + 12 + 9 = 57 cm²

4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Anit [1.1K]
Well the area of a trapezoid is defined by the following formula:
A = \frac{1}{2}(b_{1} + b_{2})h where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.

Let's plug in what we know into this formula:
h = 7  the perpendicular distance between the two bases
b₁ = 15  the shorter parallel side
b₂ = 25  the longer parallel side made up of 4 + 15 + 6
so, A = \frac{1}{2} (15+25)(7)=140

This is in square units of measure of course, so 140 in² 
8 0
3 years ago
If the legs of a triangle are 6cm and 5cm, find the area of the triangle
Stels [109]
15 cm^2


A= 5*6/2= 30/2= 15 cm^2
8 0
2 years ago
Read 2 more answers
If an intravenous fluid is adjusted to deliver 15 mg of medication to a patient per hour, how many milligrams of medication are
adelina 88 [10]

Answer: 0.125 mg per half minute

Step-by-step explanation:

15mg per hour can be written as 15mg/h

To find out how many mg of medication are delivered per half minute you can convert from hour to minutes

There are 60 minutes in 1 hour, so you can use the conversion factor (1h/60 min) and multiply the expression by it

15 mg/h (1h/60min) = 0.25 mg/min

But the question is per half minute so you have to multiply and divide the previous expression by 0.5 (To obtain 0.5 min in the denominator, which is half minute)

Then,

(0.25 mg/min ) (0.5/0.5) = 0.125 mg/ 0.5 min (0.125 mg per half minute)

8 0
3 years ago
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